Count balls between two cricket over readings

To find valid balls between two over readings, convert each reading to balls and subtract. The digits after the dot count balls, not decimal tenths.

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Convert each endpoint

For an over reading a.b, calculate six times a plus b, where b is a valid-ball count from zero to five. Keep both endpoints within the same innings and confirm that the score source has not changed the over allocation.

Use the difference for the question asked

The difference counts valid balls between the two states. It does not count every physical delivery if wides or no-balls occurred, and it does not tell you how many runs were scored without both totals.

Keep examples separate from a live match

These numbers are worked examples. For a current IPL match, use its actual teams, innings, target, over allocation and status. A saved cricket graphic can illustrate score fields but cannot supply a live result. Match runs, fantasy contest points and video coverage are also different services and measurements. Read the contest rules for points and the broadcaster terms for viewing access.

A practical example

From 7.2 to 9.1 overs: 7×6+2=44 valid balls, and 9×6+1=55. The difference is 11 valid balls. Subtracting 7.2 from 9.1 as ordinary decimals would give a misleading representation.

What a completed answer looks like

Both endpoints are converted to valid balls, and the difference is described in balls within the same innings.

Choose another specific COME guide

Read the wider cricket and IPL guide

Read the definition of a valid over

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